In this topic you match a problem to a named distribution and use its stored formula. You check the conditions, set the parameters, and compute.
A problem belongs here when it fits one of four setups. Counting successes in a fixed number of trials is binomial. Waiting for the first success is geometric. Counting events at a steady average rate is Poisson. A continuous measurement with a supplied table is normal.
You will practice: Binomial distribution, Geometric distribution, Normal distribution and standardizing, Poisson distribution and thinning.
12 problems, each with a worked answer. Verified by an independent second solve.
Work them on paper, in order; difficulty ramps gently.
1.
Basic
A router sends 4 packets across a congested link. Each packet is dropped independently with probability 0.2. What is the probability that exactly 1 of the 4 packets is dropped?
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Answer: 0.4096
The number of dropped packets is binomial with n = 4 and p = 0.2.
P(X=1)=(14)(0.2)(0.8)3=4×0.2×0.512=0.4096
2.
Basic
You roll a fair six-sided die repeatedly until you get the first six. What is the probability that the first six appears on exactly the third roll?
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Answer: 21625
The roll number of the first six is geometric with p = 1/6.
P(X=3)=(65)2⋅61=21625
3.
Basic
A gardener plants 5 tomato seeds. Each seed germinates independently with probability 0.7. What is the probability that exactly 4 of the 5 seeds germinate?
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Answer: 0.36015
The number of germinating seeds is binomial with n = 5 and p = 0.7.
P(X=4)=(45)(0.7)4(0.3)=5×0.2401×0.3=0.36015
4.
Basic
Each scratch-off lottery ticket from a large roll is a winner independently with probability 0.25. You scratch tickets one at a time. What is the probability that your first winning ticket is exactly the 4th one you scratch?
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Answer: 25627
The trial number of the first win is geometric with p = 0.25.
P(X=4)=(0.75)3(0.25)=25627≈0.1055
5.
Basic
An archer shoots 3 arrows at a target. Each arrow hits the bullseye independently with probability 0.9. What is the probability that all 3 arrows hit the bullseye?
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Answer: 0.729
The number of bullseyes is binomial with n = 3 and p = 0.9.
P(all 3 hit)=0.93=0.729
6.
Basic
A telemarketer calls households one at a time. Each call results in a sale independently with probability 0.1. What is the probability that the first sale occurs on exactly the fourth call?
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Answer: 0.0729
The call number of the first sale is geometric with p = 0.1.
P(X=4)=(0.9)3×0.1=0.0729
7.
Basic
A fair coin is tossed 4 times. The tosses are independent. What is the probability that all 4 tosses land heads?
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Answer: 161
Each toss is heads with probability 1/2, so multiply the four probabilities.
(21)4=161
8.
Basic
A spinner lands on red with probability 1/3 on each spin. Spins are independent. You spin until red appears for the first time. What is the probability that the first red is on exactly the second spin?
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Answer: 92
Geometric pattern: one failure, then the first success.
(32)(31)=92
9.
Basic
A basketball player makes each free throw independently with probability 0.6. She takes 5 free throws. What is the probability that she makes exactly 3 of them?
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Answer: 0.3456
The number of makes is Binomial(5, 0.6). Use the binomial pmf at k = 3.
(35)(0.6)3(0.4)2=10⋅0.216⋅0.16=0.3456
10.
Basic
A bakery receives custom cake orders at an average rate of 2 orders per day. The number of orders in a day follows a Poisson distribution. What is the probability that the bakery receives exactly 3 orders tomorrow?
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Answer: 34e−2≈0.1804
Use the Poisson pmf with λ = 2 at k = 3.
e−23!23=34e−2≈0.1804
11.
Basic
The heights of adult women in a city are normally distributed with mean μ = 165 cm and standard deviation σ = 5 cm. What is the probability that a randomly chosen woman is taller than 170 cm? Use Φ(1) = 0.8413.
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Answer: 0.1587
Standardize 170 and take the upper tail.
z=5170−165=1
P(X>170)=1−Φ(1)=1−0.8413=0.1587
12.
Basic
A wildlife camera is set up in a forest. On each night, independently, it captures a photo of a fox with probability 0.2. What is the probability that the first fox photo happens after night 3, that is, the first 3 nights all have no fox photo?
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Answer: 0.512
The first success comes after night 3 exactly when the first 3 nights are all failures.
(0.8)3=0.512